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Full text of "Text Book Of Mechanical Engineering"

Appendix L

761

centre of the beam, caused by the load en. In short, as B^
oc/ oc S, M! must equal M2, in order to cause the least stress
in the beam. Assuming the lettered dimensions to represent

PADDLE.   FL.O/\T

BO,^H       Fjuof.753.
1fe,__

<:/?/t/vr

J&0.754,

feet, and the load to   be i Ib.  per   foot  run, then the  bending
moments are as follows:

(i)    Due to distributed load at b = 

(2;    Due to distributed load at a - x =---------

(3 )    Due to concentrated load at E = x(a - K)
(See also Fig. 400.)

(2 x}2     x'2
(4)    Due to distributed load at 2 x = ^-5 = :

But (24-3) = Mj              and (i) = M1

also (4) = M2

.-.    (4)= (i),

and kv=

Again    (4) == (2 -f 3)

(a - sc

a - oc)

l-b

or    2 b^ = dP
and   b~

I H-

.= = '414 /